JEE MAIN - Physics (2023 - 10th April Morning Shift - No. 5)
The equivalent capacitance of the combination shown is :
_10th_April_Morning_Shift_en_5_1.png)
$$\frac{C}{2}$$
4C
$$\frac{5}{3}$$C
2C
คำอธิบาย
_10th_April_Morning_Shift_en_5_2.png)
Capacitors numbered (3) and (4) are short circuit as their both plates are connected to terminal B which makes the potential difference across both to be zero. The equivalent circuit is as shown :
_10th_April_Morning_Shift_en_5_3.png)
Hence $C_{A B}=2 C$ as capacitors numbered (1) and (2) are connected in parallel.